The standard equation of a line in point-slope form is expressed as;
y-y0 = m(x-x0) where:
m is the slope
b is the y-intercept.
Given the following
Slope = 1/4
(x0, y0) = (-2, -2)
The equation becomes;
y-(-2) = 1/2(x-(-2))
y+2 = 1/2(x+2)
2(y+2) = x+2
2y+4 = x+ 2
2y-x = 2-4
2y-x = -2
For the line through the point (2, 0) with a slope of 1/4
y - 0 = 1/4(x-2)
y = 1/4(x-2)
4y = x- 2
4y - x = -2
Find the plotted lines below:
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