Answer:
The coefficient of friction between the block and the slope is 0.16.
Explanation:
We can find the coefficient of friction between the block and the slope by using Newton's second law:
[tex] \Sigma F = ma [/tex]
[tex]P_{x} -\mu N = ma[/tex]
[tex] mgsin(\theta) - \mu mgcos(\theta) = ma [/tex] (1)
Where:
m: is the mass of the block = 5.0 kg
a: is the acceleration = 4.2 m/s²
θ: is the angle = 34°
μ: is the coefficient of friction =?
g: is the gravity = 9.81 m/s²
By entering the above values into equation (1) we have:
[tex] gsin(\theta) - \mu gcos(\theta) = a [/tex]
[tex] \mu = \frac{gsin(\theta) - a}{gcos(\theta)} = \frac{9.81 m/s^{2}*sin(34) - 4.2 m/s^{2}}{9.81 m/s^{2}*cos(34)} = 0.16 [/tex]
Therefore, the coefficient of friction between the block and the slope is 0.16.
I hope it helps you!
