Answer:
i dont exactly know the answer but i do know the formula
Explanation:
1/ 1/R1 + 1/ R2+
The voltage drop across the resistor [tex]R_{2}[/tex] is of 10 V.
Given data:
The voltage of the power supply is, V' = 15 V.
The series resistors are [tex]R_{1}[/tex] and [tex]R_{2}[/tex].
The voltage drop across the resistor [tex]R_{1}[/tex] is, V'' = 5 V.
We know that for the series resistance, the net resistance is equal to the sum of each resistance maintained in a circuit. Then,
[tex]R = R_{1} + R_{2}[/tex]
Using the Ohm's law,
[tex]\dfrac{V'}{I} = \dfrac{V''}{I}+ \dfrac{V'''}{I}[/tex]
Here, V''' is the voltage drop across the resistor [tex]R_{2}[/tex].
Solving as,
[tex]V' = V'' + V'''\\\\15 = 5 +V'''\\\\V'''=10 \;\rm V[/tex]
Thus, we can conclude that the voltage drop across the resistor [tex]R_{2}[/tex] is of 10 V.
Learn more about the series connection of resistors here:
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