Answer:
The volume of the geometric solid produced is 391 cubic cm ⇒ A
Step-by-step explanation:
When a right triangle is rotated about its vertical leg 360°, then it formed a cone its radius is the horizontal leg of the triangle and its height is the vertical lege of the triangle.
The rule of the volume of the cone is V = [tex]\frac{1}{3}[/tex] π r² h, where
- r is the radius of its base
- h is the length of its height
∵ Triangle XYZ is rotated 360° about the vertical side YZ
∴ It formed a cone with a radius = XZ and a height = YZ
∵ [tex]\frac{YZ}{XZ}=tan(60)[/tex]
∵ YX = 6√3
∴ [tex]\frac{6\sqrt{3}}{XZ}=tan(60)[/tex]
∵ tan(60) = √3
∴ [tex]\frac{6\sqrt{3}}{XZ}[/tex] = √3
→ By using cross multiplication
∴ 6√3 = XZ(√3)
→ Divide both sides by √3
∴ 6 = XZ
∵ XZ = r and YZ = h
∴ r = 6 and h = 6√3
→ By using the rule of the cone above
∵ V = [tex]\frac{1}{3}[/tex] (π) (6)² (6√3)
∴ V ≅ 391 cm³
∴ The volume of the geometric solid produced is 391 cubic cm
