The mass of CO₂ gas = 4.312 g
Reaction
NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)
Find limiting reactant
mol NaHCO₃
[tex]\tt \dfrac{8.24}{84,007 }=0.098[/tex]
mol HCl
[tex]\tt \dfrac{4.41}{36.5}=0.121[/tex]
Limiting reactant : NaHCO₃ (smaller)
mol CO₂ = mol NaHCO₃ = 0.098
mass CO₂ :
[tex]\tt 0.098\times 44=4.312~g[/tex]
