Answer:
0.74 moles of oxygen are required for combustion
Explanation:
Given data:
Number of moles of oxygen required = ?
Mass of Mg = 35.5 g
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 35.5 g/ 24 g/mol
Number of moles = 1.48 mol
Now we will compare the moles of Mg with oxygen.
Mg : O₂
2 : 1
1.48 : 1/2×1.48 = 0.74 mol
0.74 moles of oxygen are required for combustion.
