Answer:
8.06 m/s
Explanation:
It is given that,
Mass of a swimmer, m = 72 kg
He jumps from a diving board 3.25 m above the water.
We need to find the speed just as he hits the water if he jumps straight up. Using the conservation of energy to fin it as follows :
[tex]mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 10\times 3.25}\\\\ v=8.06\ m/s[/tex]
So, the required speed is 8.06 m/s.