Answer:
i) a = 0.977 [m/s²]
ii) x = 115.06 [m]
Explanation:
In order to determine the acceleration, we must use the following equation of kinematics.
[tex]v_{f} ^{2} =v_{o} ^{2} -2*a*x[/tex]
where:
Vf = final velocity = 7 [m/s]
Vo = initial velocity = 15 [m/s]
a = acceleration [m/s²]
x = displaciment = 90 [m]
Now replacing:
[tex](7)^{2} =(15)^{2} -2*a*90\\2*a*90 = 15^{2} - 7^{2} \\180*a=176\\a=0.977[m/s^{2}][/tex]
When the bus coming to rest.
[tex]v_{f}^{2} =v_{o} ^{2} -2*a*x\\0 = 15^{2} -2*0.977*x\\x = 115.06[m][/tex]
