Answer:
14m/s
Explanation:
Given parameters:
Radius of the curve = 50m
Centripetal acceleration = 3.92m/s²
Unknown:
Speed needed to keep the car on the curve = ?
Solution:
The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.
It is given as;
a = [tex]\frac{v^{2} }{r}[/tex]
a is the centripetal acceleration
v is the speed
r is the radius
Now insert the parameters and find v;
v² = ar
v² = 3.92 x 50 = 196
v = √196 = 14m/s
The speed that is necessary for keeping the car on the curve is 14 m/s.
Given that,
Based on the above information, the calculation is as follows:
We know that
[tex]a = v^2 \div r[/tex]
Here a denotes the centripetal acceleration.
v denotes the speed.
And, r denotes the radius.
So,
[tex]v^2 = ar\\\\= \sqrt(3.92 \times 50)\\\\= \sqrt{196}[/tex]
= 14 m/s
Therefore we can conclude that the speed that is necessary for keeping the car on the curve is 14 m/s.
Learn more: brainly.com/question/22610586
