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It rained all day on Father's Day and the temperature dropped ten and seven tenth degrees. The next day the rain stopped and the temperature rose twelve and six tenths degrees. If the temperature at the beginning of Father's Day was sixty five and eight tenths degrees, what was the temperature at the end of the day after Father's Day?

Write numerical answer only (no sentences, no units) Pls help I'll give brainliest

Respuesta :

Answer:

[tex]67\frac{7}{10}[/tex] or [tex]67.7[/tex]°

Step-by-step explanation:

First let's interpret the wording. It mentions that on the first day the temperature dropped [tex]10\frac{7}{10}[/tex]. Then on the second day the temperature increased by [tex]12\frac{6}{10}[/tex]. Then they tell us that if the beginning temperature was [tex]65\frac{8}{10}[/tex] what would the temperature be at the end of the of the second day. So since the temperature decreased the first day we should subtract [tex]10\frac{7}{10}[/tex] from [tex]65\frac{8}{10}[/tex]. That will give us [tex]55\frac{1}{10}[/tex]. Now for the second day the temperature increased so we will add [tex]12\frac{6}{10}[/tex] to [tex]55\frac{1}{10}[/tex] and that will give us [tex]67\frac{7}{10}[/tex] and if you want it in a decimal it will be [tex]67.7[/tex].

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