Answer:
[tex]$AlH^-_4, SiH_4 \text{ and}\ PH^+_4$[/tex]
Explanation:
The elements belonging to third period which corresponds to B,C and N are Al, Si and P. All these elements in the third period tries to combine with four of hydrogen atoms and form an analogous species.
The formulae of these species are given as [tex]$AlH^-_4, SiH_4 \text{ and}\ PH^+_4$[/tex]
All these species have a central atom which has four electron domain and the geometry of the electron domain is tetrahedral. The hybridization which corresponds to the geometry of tetrahedral electron domain is [tex]$sp^3$[/tex] .
So [tex]$AlH^-_4, SiH_4 \text{ and}\ PH^+_4$[/tex] have the same hybridization at the central atom such as [tex]$BH^-_4, CH_4 \text{ and}\ NH^+_4$[/tex] .
The formulas of the analogous species of the elements of period 3 are [tex]\rm AlH_4, SiH_4, and\; PH_4[/tex]. These elements have the same hybridization ate the central atom.
Analogous species are those that have similar functions.
In chemistry, the elements that are present in the same column have similar properties.
These elements with similar properties are called analogous species of the periodic table.
Thus, the formulas are [tex]\rm AlH_4, SiH_4, and\; PH_4[/tex], and they have the same hybridization at the central atom.
Learn more about analogous species
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