Answer:
8 bits
Explanation:
Given
Decimal Value = 200
Required
Determine minimum number of bits to store the value
Represent the decimal value with N and the number of bits with n
The relationship between n and N is:
[tex]2^n = N[/tex]
Substitute 200 for N
[tex]2^n = 200[/tex]
Take Log of both sides
[tex]Log2^n = Log200[/tex]
Apply law of indices
[tex]nLog2 = Log200[/tex]
Make n the subject
[tex]n = \frac{Log200}{Log2}[/tex]
[tex]n = 7.64385618977[/tex]
We need n to be an integer; So, we have to approximate
[tex]n = 8[/tex]
