the perimeter of trapezoid BMNC is 35
Given :
In triangle ABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. If MN = 8, ML = 5, and NL = 6
By midpoint theorem ,
[tex]BC= 2 \cdot MN\\BC=2 \cdot 8\\BC=16[/tex]
M is the midpoint of AB, AB= 2 times NL
BM=NL
BM=6
N is the midpoint of AC
AC is 2 times of ML
NC=ML
NC=5
Perimeter of trapezoid is sum of all the sides
Perimeter of BMNC = BM+MN+NC+CB
Perimeter =[tex]6+8+5+16=35[/tex]
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