Answer:
75240J
Explanation:
Given parameters:
Mass of water = 300g
Initial temperature of the water = 85°C
Final temperature = 25°C
Unknown:
Amount of heat released = ?
Solution:
The amount of heat released in this cooling process can be calculated using the expression below;
H = m x c x (t₂ - t₁)
m is the mass
c is the specific heat capacity of water = 4.18J/g°C
t is the temperature
Insert the parameters and solve;
H = 300 x 4.18 x (25 - 85) = -75240J
The negative symbol denotes heat loss.
