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9.45g of acetic acid are present in vinegar. Hope this helps and pls give thanks!!
The mass of acetic acid would be 9.435 grams, in 185 mL of vinegar if Vinegar contains 5.00% acetic acid (by mass) and its density is 1.02g / mL
What is density?
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
Generally, the density of any substance is expressed by the greek symbol ρ. The density is the reciprocal of the specific volume of any substance.
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By using the above formula for density
ρ = mass / volume
As given in the problem Vinegar contains 5.00% acetic acid (by mass) and its density is 1.02g / mL
The total mass of the vinegar
mass= ρ×volume
=1.02×185
=188.7
As given Vinegar contains 5.00% acetic acid (by mass)
the mass of acetic acid = 5×188.7/100
=9.435 gram
Thus, the mass of acetic acid comes out to be 9.435 grams
Learn more about density from here
brainly.com/question/15164682
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