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Two particles each of
positive charges 2.24×10^-12C are
Situated 40cm apart from
each in a vacuum. Calculate
the force acted on the particle-
Take, permutivity knot=8.854X10-12 Nm / C^2​

Respuesta :

Answer:

2.48*10^-22 N

Explanation:

Net Force = k m1m2 / r^2

[tex]\frac{8.854*10^-12*2.24*10^-12*2}{0.4^2} = 2.48*10^-22 N[/tex]

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