Answer:
1. Length in terms of width is 5000/W meters
2. Solving for b gives us: [tex]b = \frac{2A}{h}[/tex]
3. Solving for t gives us: [tex]t = \frac{i-f}{g}[/tex]
4. Solving for P gives us:
[tex]W = \frac{P}{2} - L[/tex]
Step-by-step explanation:
1. The formula A = L x W gives the area of a rectangle R. The area of a rectangular garden is 5000sqm. What is the garden's length in terms of width?
Given that
[tex]A= L*W[/tex]
Also given that A = 5000 square meters.
Now,
[tex]5000 = L * W[/tex]
Dividing both sides by W
[tex]\frac{L*W}{W} = \frac{5000}{W}\\L = \frac{5000}{W}[/tex]
So,
Length in terms of width is 5000/W meters
2. The formula for the area of a triangle is A = ½ bh, where b is the length of the base, and h is the height. Solve for b
The given formula is:
[tex]A = \frac{1}{2}bh[/tex]
Solving it for b means that the we have to isolate b
So,
[tex]A = \frac{1}{2}bh\\2A = 2. \frac{1}{2}bh\\2A = bh\\\frac{2A}{h} = \frac{bh}{h}\\b = \frac{2A}{h}[/tex]
Solving for b gives us: [tex]b = \frac{2A}{h}[/tex]
3. The formula for an object’s final velocity is f = i – gt, where i is the object’s initial velocity, g is acceleration due to gravity, and t is time. Solve for t.
Given
[tex]f = i-gt\\Now\\f+gt = i\\gt = i-f\\\frac{gt}{g} = \frac{i-f}{t}\\t = \frac{i-f}{t}[/tex]
Solving for t gives us: [tex]t = \frac{i-f}{g}[/tex]
4. Own Question: The perimeter of a rectangle is given by P = 2(L+W). Solve for width.
[tex]P = 2(L+W)\\\frac{P}{2} = \frac{2(L+W)}{2}\\\frac{P}{2} = L+W\\\frac{P}{2} - L = W[/tex]
Solving for P gives us:
[tex]W = \frac{P}{2} - L[/tex]
