What volume is occupied by 3.00 moles of nitrogen under a pressure of 202 kPa and a temperature of 323K? R = 8.314 kPa L/mol K INICI​

Respuesta :

rsd05

Answer:

39.9 L

Explanation:

Use PV = nRT to solve this problem.

Substitute the values known.

P is pressure, which is 202 kPa, V is volume, which we do not know, n is moles, which is 3, R is 8.314, and T is temperature, which is 323K.

Set up your equation as follows [tex]202 kPa V = 3.00mol (\frac{8.314 kPa L }{mol K} ) 323K[/tex]

Solve for V, multiply the right side of the equation and divide by the pressure, 202 kPa.

This results in Volume being 39.9 L