Write an equation in slope-intercept form for the line that passes through (6,- 3) and is parallel to y = -2x + 4.
__________________________________________________________
Parallel lines are lines with the same slope but different y-intercept.
Slope-intercept form is written as y=mx+b, where m is the slope and b is the y-intercept.
__________________________________________________________
The given line is y=-2x+4. A line parallel to this would have the same slope, which is -2. To find the y-intercept, plug the point into an equation in point-slope form.
[tex]\displaystyle \text{Point-Slope Form} \rightarrow y-y_{1}=m(x-x_{1})[/tex]
m is the slope, and since the slope is the same as the given line, m will be equal to 2.
The line is supposed to pass through a point, which is written as (x, y). In this line, it is supposed to pass (6, -3). x₁ will be the x value of the point, and y₁ will be the y value of the point. That means x₁ is 6 and y₁ is -3.
Substitute the values into the formula:
[tex]y-y_{1}=m(x-x_{1}) \rightarrow y-(-3)=2(x-6)[/tex]
When subtracting a negative number from a number or variable, the sign will change, and the number will become positive.
[tex]y-(-3)=y+3[/tex]
Here is the new equation:
[tex]y-3=2(x-6)[/tex]
Distribute the 2 to everything in the parentheses. It will be 2 times x and 2 times -6. Remember that a positive number multiplied by a negative number is negative.
[tex]2 \times x=2x\\2 \times -6=-12\\\\2(x-6)=2x-12[/tex]
Rewrite the equation:
[tex]y-3=2x-12[/tex]
Lastly, you need to move -3 to the other side, as slope-intercept form is written as y=mx+b. You can move it by adding three(+3) to both sides, which is simply doing the opposite of it(-3+3=0).
[tex]\displaystyle y-3+3=2x-12+3[/tex]
[tex]y=2x-9[/tex]
The answer to your question is [tex]\bf \displaystyle y=2x-9[/tex].
