Answer:
0.35 M
Explanation:
Using the formula; C1V1 = C2V2
Where;
C1 = concentration of initial solution
C2 = concentration of final solution
V1 = volume of initial solution
V2 = volume of final solution
Based on this question, I start with 0.0350 L of a 12.0 M hydrochloric acid solution, and dilute it with water to a new volume of 1.20 L. This means that:
C1 = 12.0 M, V1 = 0.0350 L, V2 = 1.20 L, C2 = ?
Hence, C1V1 = C2V2
12 × 0.0350 = C2 × 1.20
0.42 = 1.2C2
C2 = 0.42/1.2
C2 = 0.35 M
