Respuesta :
Answer:
[tex]T_f=343.14^{\circ} C[/tex]
Explanation:
Given that,
The heat capacity of solid iron is 0.447 J/g°C.
Mass, m = 450 g
Initial temperature, [tex]T_i=20^{\circ} C[/tex]
Let the heat transferred, Q = 65 kJ
We need to find the final temperature. The heat transferred is given by :
[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q+mcT_i=mcT_f\\\\T_f=\dfrac{Q+mcT_i}{mc}\\\\=\dfrac{65000+450\times 0.447\times 20}{450\times 0.447}\\\\=343.14^{\circ} C[/tex]
So, the final temperature is [tex]343.14^{\circ} C[/tex].
The final temperature of the iron after the heat transfer of 65 kJ will be 343.14 [tex]\rm ^\circ C[/tex].
The specific heat is the amount of heat required to raise the temperature of 1 g of substance by 1-degree celsius.
The specific heat can be given by:
Q = mc[tex]\Delta[/tex]T
Q = specific heat = 65 kJ
c= heat capacity = 0.447 J/g [tex]\rm ^\circ C[/tex]
m = mass of the iron = 450 g
[tex]\Delta[/tex]T = change in temperatue = final temperature - initial temperature
[tex]\Delta[/tex]T = final temperature - 20 [tex]\rm ^\circ C[/tex]
Putting the values in the equation:
65000 J = 0.447 J/g [tex]\rm ^\circ C[/tex] [tex]\times[/tex] 450 g
65000 J = 201.15 [tex]\times[/tex] ( final temperature - 20 [tex]\rm ^\circ C[/tex] )
Final temperature - 20 [tex]\rm ^\circ C[/tex] = 323.14
Final temperature = 343.14 [tex]\rm ^\circ C[/tex].
The final temperature of the iron after the heat transfer of 65 kJ will be 343.14 [tex]\rm ^\circ C[/tex].
For more information about heat transfer, refer to the link:
https://brainly.com/question/18336701
