Respuesta :

Answer:

1.343 atm

Explanation:

We are given the following;

Pressure, p = ?

Volume v = 27 L

Mass of oxygen = 44.9 g

Temperature, T = 315 K

The formular relating all these variables is the equation;

PV = nRT

where R = gas constant = 0.08206 L atm / mole K

To obtain n, we use;

number of moles, n = Mass /  molar mass =  44.9 / 32 = 1.403 moles

From the ideal gas equation;

P = nRT / V

P = 1.403 * 0.08206 * 315 / 27

P = 36.27 / 27 = 1.343 atm

samueladesida43

The pressure in a 27.0-L cylinder filled with 44.9 g of oxygen gas at a temperature of 315 K is 1.34atm

IDEAL GAS LAW:

  • The pressure of a given gas can be calculated by using the ideal gas law equation as follows:

PV = nRT

Where;

  1. P = pressure
  2. V = volume
  3. n = number of moles
  4. R = gas law constant (0.0821 molK/Latm)
  5. T = temperature

  • According to this question, a 27.0-L cylinder filled with 44.9 g of oxygen gas at a temperature of 315 K.

  • The number of moles of the oxygen gas (O2) = 44.9g ÷ 32g/mol = 1.403mol

  • P × 27 = 1.403 × 0.0821 × 315

  • 27P = 36.284

  • P = 36.284 ÷ 27

  • P = 1.34atm

  • Therefore, the pressure in a 27.0-L cylinder filled with 44.9 g of oxygen gas at a temperature of 315 K is 1.34atm.

Learn more about ideal gas law equation at: https://brainly.com/question/4147359?referrer=searchResults

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