Answer:
Step-by-step explanation:
a). From the table attached,
Number in 1st column and 1st row = 1 - 1 = 0
Number in 1st column and 6th row = 6 - 1 = 5
Number in 2nd column and 4th row = 4 - 2 = 2
Number in 5th column and 2nd row = 5 - 2 = 3
Number in 6th column and 5th row = 6 - 5 = 1
b). Probability of scoring 1 = [tex]\frac{\text{Preferred outcome}}{\text{Total outcomes}}[/tex]
Preferred outcomes of getting = 10
Total outcomes = 36
Probability of scoring 1 = [tex]\frac{10}{36}[/tex]
= [tex]\frac{5}{18}[/tex]
c). Probability of occurring a score = [tex]\frac{1}{18}[/tex]
= [tex]\frac{1\times 2}{18\times 2}[/tex]
= [tex]\frac{2}{36}[/tex]
= [tex]\frac{\text{Preferred outcome}}{\text{Total outcomes}}[/tex]
Since, 5 is a number which has occurred twice
Score that has a probability of occurring of [tex]\frac{1}{18}[/tex] is 5.
