Respuesta :
Answer:
A. wordList[0] = wordList[2]
Explanation:
Required
Which line would give ["air", "rock", "air"]
From the question, we have that:
wordList = ["tree", "rock", "air"]
which means that:
wordList[0] = "tree"
wordList[1] = "rock"
wordList[2] = "air"
Analyzing the options.
A. wordList[0] = wordList[2]
This will assign the item in wordList[2] to wordList[0].
and the result would be
So:
wordList[0] = "tree"
would change to
wordList[0] = "air"
The new content of wordList would then be ["air", "rock", "air"]
Option (A) answers the question
The list variable wordList contains three string values, Hence, to obtain the list, ["air", "rock", "air"], the lines wordList[0] = wordList[2] would be used.
- List values are indexed from 0 ; hence, tree = index 0 ; rock = index 1 ; air = index 2
- To assign the the string "tree" to index 0, then wordList[2] is assigned to wordList[0].
- wordList[0] is now "air"
Hence, the required line of code would be wordList[0] = wordList[2]
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