Secant and Tangent Angles in circles.
Solve for x.

Answer:
x = 1
Step-by-step explanation:
5x + 17 = 1/2[(73x + 5) - (23x - 5)]
5x + 17 = 1/2[37x + 5 - 23x + 5]
5x + 17 = 1/2[14x + 10]
5x + 17 = 1/2 * 2(7x + 5)
5x + 17 = 7x + 5
5x - 17x = 5 - 17
-12x = - 12
x = - 12/-12
x = 1
A circle is a curve sketched out by a point moving in a plane. The value of x that will make the Secant and Tangent Angles true for the circle is 17/25.
A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the centre.
For the given circle, as per the Secant and Tangent Angles theorem, the measure of the angle formed by two tangents can be written as,
∠WVU = (arc WU + arc WU)/2
5x + 17 = [(37x + 5) + (23x - 5)]/2
2(5x + 17) = (37x + 5) + (23x - 5)
10x + 34 = 37x + 5 + 23x - 5
10x - 37x - 23x = 5 - 5 - 34
-50x = -34
x = 34/50
x = 17/25
Hence, the value of x is 17/25.
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