A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure?

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

andromache andromache · Answer 2 · 2021-11-23T16:04:09+01:00

The number of moles is 10.94 mol.

The calculation is as follows:

As per the Avogadro gases law, the no of moles at the same pressure & temperature should be proportional to the volume.

The following formula should be used:

[tex]n_1\div V_1 = n_2\div V_2\\\\n_2= (n_2\div V_1) \times V_2\\\\ = (1.59 mol\div 0.641 L) \times 4.41 L[/tex]

= 10.939 mol

= 10.94 mol

Therefore we can conclude that the number of moles is 10.94 mol.

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