Assuming a release of 173 MeV per fission reaction, calculate how many reactions must occur per second to produce a power output of 170 MW .

Respuesta :

Answer:

The number of reaction that must occur is 6.142 x 10¹⁸ reactions / second

Explanation:

Given;

energy released by the fission reaction, E = 173 MeV

power output, P = 170 MW

Convert the energy released by the fission reaction to Joules;

= 173 x 10⁶ x 1.6 x 10⁻¹⁹ J = 2.768 x 10⁻¹¹ J

Convert the output power to joules per second;

= 170 x 10⁶ J/s

The number of reactions per second that must occur is given by;

[tex]= \frac{170*10^6 \ J/s}{2.768*10^{-11} J/reaction} = 6.142 *10^{18} \ reaction/second[/tex]

Therefore, the number of reaction that must occur is 6.142 x 10¹⁸ reactions / second