Respuesta :
Formula of finding the distance : absolute value (x2-x1)^2 + (y2-y1)^2
Distance from house to school : (Under Absolute value) (x2-x1)^2 + (y2-y1)^2
( -4 - (-4) )^2 + (10 - 3 )^2 = 0 + 49 = Radical 49 = 7
Distance from house to grocery store : (using the same method) you get = Radical 1200 = 60
Distance from house to community center : (using the same method) =
Radical 85
Yes, the distance from her house to grocery store is greater then to community center
Distance from house to school : (Under Absolute value) (x2-x1)^2 + (y2-y1)^2
( -4 - (-4) )^2 + (10 - 3 )^2 = 0 + 49 = Radical 49 = 7
Distance from house to grocery store : (using the same method) you get = Radical 1200 = 60
Distance from house to community center : (using the same method) =
Radical 85
Yes, the distance from her house to grocery store is greater then to community center
The distances between two points are required.
The Distance from house to school to grocery store is greater than Distance to from house to school to community center.
The points are
[tex]H(-4,5)[/tex]
[tex]S(-4,3)[/tex]
[tex]C(6,3)[/tex]
[tex]G(-4,-9)[/tex]
The distance between the HS is
[tex]|HS|=\sqrt{(3-5)^2+(-4-(-4))^2}=2[/tex]
Distance between SG
[tex]|SG|=\sqrt{(-4-(-4))^2+(-9-3)^2}=12[/tex]
Distance from house to school to grocery store is
[tex]2+12=14[/tex]
Distance between the SC
[tex]|SC|=\sqrt{(6-(-4))^2+(3-3)^2}=10[/tex]
Distance to from house to school to community center
[tex]2+10=12[/tex]
So, the Distance from house to school to grocery store is greater than Distance to from house to school to community center.
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