Answer:
The value of sec A = - √29/5
Step-by-step explanation:
As the terminal side of angle 'A' passes through (-5,2).
so the angle is in the 2nd quadrant.
We can find the length of the hypotenuse using the Pythagorean Theorem
[tex]c^2\:\:=\:\left(-5\right)^2\:+\:2^2[/tex]
[tex]c^2=5^2+2^2[/tex]
[tex]c^2=25+4[/tex]
[tex]c^2=29[/tex]
[tex]c=\sqrt{29}[/tex]
As we know that
cos A = adjacent/hypotenuse
sec A = 1/cosA
= hypotenuse/adjacent
= √29/-5
= - √29/5
Therefore, the value of sec A = - √29/5
