Given:
The perimeter of a triangle is 59 cm.
The first side is 7 cm shorter than the second side.
The third side is 4 cm less than twice the length of the first side.
To find:
The length of each side.
Solution:
Let x be the second side.
Then, according to the question,
First side = x-7
Third side = 2(x-7)-4
Perimeter of a triangle is the sum of all of its sides.
[tex](x-7)+x+(2(x-7)-4)=59[/tex]
[tex]x-7+x+2x-14-4=59[/tex]
[tex]4x-25=59[/tex]
Add 25 on both sides.
[tex]4x=59+25[/tex]
[tex]4x=84[/tex]
Divide both sides by 4.
[tex]x=21[/tex]
Now,
First sides =21 - 7=14 cm
Second side = 21 cm
Third side = 2(14)-4 = 24 cm
Therefore, the three sides of triangle are 14 cm, 21 cm and 24 cm respectively.
