The moles of nitrogen gas present in 135 L at STP have been 6.02 moles.
The nitrogen gas has been assumed to be the ideal gas. For an ideal gas, at STP or standard pressure and temperature, the volume of 1mole of gas has been 22.4 L.
The STP conditions have been 273.15 K temperature, and 1 atm pressure.
Since, moles in 22.4 L gas been 1 mole. The moles in 135 L gas has been:
22.4 L = 1 mole
135 L = [tex]\rm \dfrac{1}{22.4}\;\times\;135\;moles[/tex]
135 L gas = 6.02 moles.
The moles of nitrogen gas present in 135 L at STP have been 6.02 moles.
For more information about the volume at STP, refer to the link:
https://brainly.com/question/11676583
