Answer:
(a) 6332.812 N (b) 1469.59 pounds.
Explanation:
Given that,
The surface area of the top of yu head is 25 cm x 25 cm
Area = 625 cm² = 0.0625 m²
Atmospheric pressure on it is 101325 Pa.
(a) Pressure acting on an object is given by force acting per unit area. It can be written as :
[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=101325\ Pa\times 0.0625\ m^2\\\\F=6332.812\ N[/tex]
6332.812 N of force is acting on your head at sea level.
(b) If area, A = 100 in²
We know that,
1 atm = 14.6959 pounds/in²
[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=14.6959 \ \text{Pounds}/in^2\times 100\ in^2\\\\F=1469.59\ \text{pounds}[/tex]
So, the force is 1469.59 pounds.
A. The force required to push your head at sea level is 6332.8125 N
B. The force in pound is 1469.59 lb
A. Determination of the force required at sea level.
Pressure (P) = 101325 Nm²
Area (A) = 25 cm × 25 cm = 0.25 m × 0.25 m = 0.0625 m²
P = F / A
Cross multiply
F = PA
F = 101325 × 0.0625
Therefore, the force required to push your head at sea level is 6332.8125 N
B. Determination of the force in pounds
Area (A) = 100 in²
Pressure (P) = 14.6959 pound / in²
F = PA
F = 14.6959 × 100
Learn more: https://brainly.com/question/13182194
