Answer:
The components of the force in the x and y-direction are -153.21 N and 128.56 N respectively.
Explanation:
Rectangular components of a vector
Given a vector [tex]\vec F[/tex] as an ordered pair (f,θ), where f is the magnitude of the vector and θ is the angle it forms with the positive x-direction, the rectangular components of the vector are given by:
[tex]F_x=f.\cos\theta[/tex]
[tex]F_y=f.\sin\theta[/tex]
The force of f=200N forms an angle of θ=140°. The components of the force are:
[tex]F_x=200.\cos 140^\circ[/tex]
Calculating:
[tex]F_x=-153.21~N[/tex]
[tex]F_y=200.\sin 140^\circ[/tex]
[tex]F_y=128.56~N[/tex]
The components of the force in the x and y-direction are -153.21 N and 128.56 N respectively.
