Answer:
Mass = 154.67 g
Explanation:
Given data:
Mass of aluminum chloride produced = ?
Mass of chlorine = 123.2 g
Solution:
Chemical equation:
2Al + 3Cl₂ → 2AlCl₃
Number of moles of chlorine:
Number of moles = mass/molar mass
Number of moles = 123.2 g/ 71 g/mol
Number of moles =1.74 mol
Now we will compare the moles of aluminum chloride and chlorine.
Cl₂ : AlCl₃
3 : 2
1.74 : 2/3×1.74 = 1.16 mol
Mass of AlCl₃:
Mass = number of moles × molar mass
Mass = 1.16 mol × 133.34 g/mol
Mass = 154.67 g
