Respuesta :

Answer:

rate of change = first derivative= g'(x)=-2x+6

plug -3 to 5 into that g'(x) equation, it will be your answer

Step-by-step explanation:

9514 1404 393

Answer:

  4

Step-by-step explanation:

The average rate of change of f(x) on the interval [a, b] is computed from ...

  m = (f(b) -f(a))/(b -a)

On the interval [-3, 5] the average rate of change is ...

  m = (f(5) -f(3))/(5 -(-3)) = ((-5^2 +6·5 +12) -(-(-3)^2 +6(-3) +12))/8

     = (-25 +30 +12 +9 +18 -12)/8 = 32/8

  m = 4

The average rate of change on the interval is 4.

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Alternate solution

The first derivative of the function is ...

  f'(x) = -2x +6

The average rate of change of a parabolic function on an interval is the rated of change at the midpoint of the interval. Here, the midpoint is x=(5+(-3))/2 = 1, so the average rate of change is ...

  f'(1) = -2(1) +6 = 4