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A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The player on the south end of the court hit the tennis ball with her racket at 75 kilometers per hour. How much force did the racket on the south end of the court exert on the ball?(1 point) A.1 N B.6.5 N C.7.5 N D.0.01 N

Respuesta :

Answer:

Explanation:

Given that:

Mass of ball = 0.1-kilogram

From the North End:

Acceleration of racket = 65 km/hour

Converting to m/seconds

= 65×1000/3600

65000/3600

= 18.055m/s

Ball acceleration= 10 meters per second squared

From the South End:

Acceleration of racket = 75 km/hour

Converting to m/seconds

75×1000/3600

= 75000/3600

= 20.833m/s

Now,

18.055m/s = 10m/s^2

20.833m/s = x

18.055m/s × x = 20.833m/s × 10m/s^2

18.055m/s × x = 208.33

x = 208.33/18.055m/s

X = 11.538m/s^2

Hence, the ball accelerated at the rate of 11.538m/s^2 in the South End.

F = ma

Where a = 11.538m/s^2

m = 0.1kg

F = 0.1×11.538m/s^2

F = 1.15N

Answer: A : 1 N

Explanation The player on the south end of the court hit the tennis ball with her racket at 75 kilometers per hour. Notice that it say per hour well all you need to do is to convert in into minutes then seconds. 1 hour has 60 minutes in it so if you divide 75 by 60 than you will get 1.25 and then you can round it up so that will give you 1 newtons(N). this is what i did to get the answer im not sure if this is how your supposed to do it but i got it right so i have to tell you how i did it.