Answer:
When the person is drunk the car travels 20.1 meters more than when the person is sober. The distance traveled by car is:
Person drunk: 28.1 m
Person sober: 8 m
Explanation:
The distance traveled can be found using the following equation:
[tex] v = \frac{x}{t} \rightarrow x = v*t [/tex]
Where:
v: is the speed = 90 km/h
t: is the time
When the person is sober, the time that takes to hit the brakes is 0.320 s, so we have:
[tex] x = v*t = 90 \frac{km}{h}*\frac{1 h}{3200 s}*0.320 s = 8 \cdot 10^{-3} km = 8 m [/tex]
And when the person is drunk, the time is 1.00 s, hence the distance is:
[tex] x = v*t = 90 \frac{km}{h}*\frac{1 h}{3200 s}*1 s = 0.0281 km = 28.1 m [/tex]
The distance traveled by the car when the person is drunk compared when the person is sober is:
[tex] d = 28.1 m - 8 m = 20.1 m [/tex]
Therefore, when the person is drunk the car travels 20.1 meters more than when the person is sober.
I hope it helps you!
