Answer:
0.0432 m^3/s
Explanation:
Internal diameter of smaller pipes = 2.5 cm = 0.025 m
pipa wall thickness = 3 mm = 0.003 m
internal diameter of larger pipes = 8 cm = 0.8 m
velocity of region between smaller and larger pipe = 10 m/s
Calculate discharge in m^3/s
First we calculate the area of the smaller pipe
A = [tex]\pi Dt[/tex] = [tex]\pi ( 0.025 ) ( 0.003 )[/tex] = 0.00023571 m^2
next we calculate area of fluid between the smaller pipes and larger pipe
A = [tex][\frac{\pi }{4} D^{2} _{L} ] - 3(A_{s})[/tex]
= [tex][ \frac{\pi }{4} (0.08 )^2 - 3 ( 0.00023571 )][/tex]
= [ 0.00502857 - 0.00070713 ]
= 0.00432144 m^2
hence the discharge in m^3/s
Q = AV
= 0.00432144 * 10
= 0.0432 m^3/s
