Given :
An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away.
To Find :
The airplane’s angle of decent.
Solution :
Height of plane, h = 2600 m.
Horizontal distance of airplane from vertices is, d = 56 km = 56000 m.
Let, angle of depression is Ф.
So,
[tex]tan \ \phi = \dfrac{56000}{2600}\\\\tan \ \phi = 21.54\\\\\phi = 87.34^o[/tex]
Therefore, the angle of decent is 87.34°.
Hence, this is the required solution.
