Consider separate solutions of NaOH and KClmade by dissolving 100.0 g of each solute in 250.0 mL of solution. Calculate the concentration of each solution in units of molarity.

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Answer:

Explanation:

MW of NaOH = 40 g/mol

MW of KCl = 74.55 g/mp;

250 mL = .25 L

100g NaOH / 40 g = 25 mol

100g KCl/ 74.55g = 1.34 mol

Molarity of NaOH: 25/.25 = 100M

Molarity of KCl: 1.34/.25 = 5.36 M

100M is the concentration of NaOH.

5.36 M is the concentration of  KCl.

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

The scientific noun molarity describes the concentration of a substance as measured by the number of moles divided by the volume of the solution in litres.

[tex]Molality = \frac{Moles \;solute}{Volume\; of \;the \;solution \;in \;litres}[/tex]

Molecular weight of NaOH = 40 g/mol

Molecular weight of KCl = 74.55 g/mp;

250 mL = .25 L

100g NaOH ÷ 40 g = 25 mol

100g KCl ÷ 74.55g = 1.34 mol

Molarity of NaOH: 25 ÷ .25 = 100M

Molarity of KCl: 1.34 ÷ .25 = 5.36 M

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