Find the length of segment JK with endpoints J(4, 8) and K(-1, -2). Leave the answer as a radical. Simplify if necessary

Answer:
The length of segment JK is 5[tex]\sqrt{5}[/tex] ⇒ C
Step-by-step explanation:
The formula of the distance between the two points (x1, y1) and (x2, y2) is
d = [tex]\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}[/tex]
Let us use the formula above to solve the question
∵ Jk is a line segment
∵ J = (4, 8) and K = (-1, -2)
∴ x1 = 4 and y1 = 8
∴ x2 = -1 and y2 = -2
→ Substitute them in the formula above
∵ JK = [tex]\sqrt{(-1-4)^{2}+(-2-8)^{2}}[/tex]
∴ JK = [tex]\sqrt{(-5)^{2}+(-10)^{2}}[/tex]
∴ Jk = [tex]\sqrt{25+100}[/tex]
∴ Jk = [tex]\sqrt{125}[/tex]
→ Simplify the root
∵ 125 = 5 × 5 × 5
∴ [tex]\sqrt{125}[/tex] = 5[tex]\sqrt{5}[/tex]
∴ JK = 5[tex]\sqrt{5}[/tex]
∴ The length of segment JK is 5[tex]\sqrt{5}[/tex]