contestada

The rate constant for the radioactive decay of tritium 3H is 0.056 1/yr. The percentage of tritium remaining after 50 years is:_________

Respuesta :

Answer:

6.05%

Explanation:

From the question given above, the following data were obtained:

Decay constant (K) = 0.0561 /yr

Time (t) = 50 years

We can obtain the percentage of tritium remaining after 50 years by using the following formula:

Log (N₀/N) = kt /2.303

NOTE:

N₀ is the original amount.

N is the amount remaining.

K is the decay constant.

t is the time

Log (N₀/N) = (0.0561 × 50) /2.303

Log (N₀/N) = 2.805/2.303

Log (N₀/N) = 1.218

Take the anti log of 1.218

(N₀/N) = anti log (1.218)

(N₀/N) = 1.218

N₀/N = 16.52

Invert and multiply by 100 to obtain the percentage.

N/N₀ = 1/16.52 × 100

N/N₀ = 6.05%

Thus, the percentage of tritium remaining after 50 years is 6.05%

Answer:

6.08% remains after 50 years

Explanation:

The radioactive decay follows the equation:

Ln[A] = -kt + Ln [A]₀

Where [A] is concentration of reactant after time t, [A]₀ is its initial concentration, k is rate constant and t is time.

Assuming its Initial concentration is 100%

Time is 50 yr

k is 0.056 yr⁻¹

And [A] is our incognite

Ln[A] = -0.056 yr⁻¹*50yr + Ln [100%]

ln[A] = 1.805

[A] =

6.08% remains after 50 years