Answer:
3.44 × 10⁻²⁰ g Na
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
900 atoms Na
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Na - 22.99 g/mol
Step 3: Convert
[tex]900 \ atoms \ Na(\frac{1 \ mol \ Na}{6.022 \cdot 10^{23} \ atoms \ Na} )(\frac{22.99 \ g \ Na}{1 \ mol \ Na} )[/tex] = 3.4359 × 10⁻²⁰ g Na
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
3.4359 × 10⁻²⁰ g Na ≈ 3.44 × 10⁻²⁰ g Na
