Calculate the number of gold atom
present in 0.6g of 18 carat gold (24 carat
gold is taken as 100%
where and amu of
gold in 197
Teacher's Signature.

Respuesta :

The number of gold atom : 1.204 x 10²¹

Further explanation

Given

0.6 g of 18 carat gold

mass number of gold = 197

24 carat as 100% gold

Required

The number of gold atom

Solution

Percentage of gold in 18 carat :

[tex]\tt \dfrac{18}{24}\times 100\%=75\%[/tex]

Mass of gold in 0.6 g of 18 carat :

[tex]\tt 75\%\times 0.6~g=0.45~g[/tex]

mol :

[tex]\tt mol=\dfrac{mass}{MW}=\dfrac{0.45}{197}=0.0023[/tex]

A mole is a number of particles(atoms, molecules, ions)  in a substance

1 mole = 6.02.10²³ particles  

So the number of gold atom :

[tex]\tt 0.0023\times 6.02\times 10^{23}=1.204\times 10^{21}[/tex]