HELP HELP HELP HELP HELP HELP HELP

Answer:
[tex]h(x)=\frac{1}{5}x[/tex]
Step-by-step explanation:
[tex]6x+y=4x+11y\\\\6x-4x=11y-y\\\\2x=10y\\\\y=\frac{2x}{10}\\\\y=\frac{1}{5}x[/tex]
so h(x) is
[tex]h(x)=\frac{1}{5}x[/tex]