Answer:
T₂ = 421.4 K
Step-by-step explanation:
The temperature, T, of a given mass of gas varies inversely with its Volume,V.
[tex]T\propto \dfrac{1}{V}\\\\V_1T_1=V_2T_2[/tex]
We have,
V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K
V₂ = 70 cm₃
We need to find the new temperature of the gas. Using the above relation to find T₂.
[tex]T_2=\dfrac{V_1T_1}{V_2}\\\\T_2=\dfrac{98\times 301}{70}\\\\T_2=421.4\ K[/tex]
Hence, the required temperature of the gas is 421.4 K.
