Answer:
[tex]a = 16\ m/s^2[/tex]
Explanation:
When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:
[tex]v_f^2=v_o^2+2ax[/tex]
Where:
vf = final velocity
vo = initial velocity
a = acceleration
x = distance
Solving for a:
[tex]\displaystyle a=\frac{v_f^2-v_o^2}{2x}[/tex]
The car travels a distance of x=200 m and the velocities are:
vo = 216 Km/h
vf = 360 Km/h
Both velocities must be converted to meters by seconds.
vo = 216 Km/h *1000/3600 = 60 m/s
vf = 360 Km/h *1000/3600 = 100 m/s
The acceleration is:
[tex]\displaystyle a=\frac{100^2-60^2}{2*200}[/tex]
[tex]\displaystyle a=\frac{10000-3600}{400}[/tex]
[tex]\displaystyle a=\frac{6400}{400}[/tex]
[tex]\mathbf{a = 16\ m/s^2}[/tex]
