Answer:
0.375 moles of CaCO₃ are required
Explanation:
Given data:
Number of moles of sulfamic acid = 0.75 mol
Number of moles of calcium carbonate required = ?
Solution:
Chemical equation:
2H₃NSO₃ + CaCO₃ → Ca(SO₃NH₂)₂ + CO₂ + H₂O
Now we will compare the moles of H₃NSO₃ and CaCO₃ .
H₃NSO₃ : CaCO₃
2 : 1
0.75 : 1/2×0.75 = 0.375 mol
Thus, 0.375 moles of CaCO₃ are required.
The moles of the product and the reactant in the reaction is given by the stoichiometric law. The moles of calcium carbonate in the reaction is 0.375 mol.
The stoichiometric law defines that the moles of the reactant and the product in the reaction is equivalent to the stoichiometric coefficient in the balanced chemical equation.
From the given balanced chemical equation, 1 mole of calcium carbonate reacts with 2 moles of sulfamic acid.
The moles of calcium carbonate react with 0.75 moles of sulfamic acid is:
[tex]\rm 2\;mol\;H_3NSO_3=1\;mol\;CaCO_3\\0.75\;mol\;H_3NSO_3=\dfrac{1}{2}\;\times\;0.75\;mol\;CaCO_3\\ 0.75\;mol\;H_3NSO_3=0.375\;mol\;CaCO_3[/tex]
The moles of calcium carbonate in the reaction will be 0.375 mol.
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