Answer:
16.7 J/km
Explanation:
Given that,
Force acting on an elastic band = 5 N
We need to find the rate at which its entropy changes as it stretches.
The relation between the force and the change in entropy per unit length is given by :
[tex]F=-T\dfrac{dS}{dL}[/tex] ...(1)
Where
T is temperature
For room temperature, T = 298 K
dS/dl is the change in entropy
Put values in equation (1).
[tex]\dfrac{dS}{dl}=\dfrac{F}{T}\\\\=\dfrac{5}{298}\\\\=0.0167\ J/m\\\\=16.7\ J/km[/tex]
Hence, the required rate at which its entropy changes is 16.7 J/km.
