Respuesta :
Answer:
0.6 M
Explanation:
The concentration can be expressed as molarity as follows:
- Molarity = NaCl moles / liters of solution
We are already given the number of moles (0.150 mol) so we need to calculate the liters of solution.
We convert mL to L:
- 250.0 mL * [tex]\frac{1L}{1000mL}[/tex] = 0.250 L
Now we can calculate the molarity of the NaCl solution:
- Molarity = 0.150 mol / 0.250 L = 0.6 M
The concentration of 0.150 moles of Sodium chloride in 250 mL solution is 0.6M.
How do we calculate concentration?
Concentration will be calculated in terms of molarity and molarity will define as the number of moles of solute present in per litre of the solution.
Given moles of NaCl = 0.150 moles
Volume of solution = 250mL = 0.25L
Molarity of NaCl will be calculated as:
M = 0.150/0.25
M = 0.6 M
Hence required molarity is 0.6M.
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